PLEASE HELP ME!!!!What are the discontinuity and zero of the function f(x) =x^2+6x+8 over x+4A)Discontinuity at (4, 6), zero at (−2, 0)B)Discontinuity at (4, 6), zero at (2, 0)C)Discontinuity at (−4, −2), zero at (−2, 0)D)Discontinuity at (−4, −2), zero at (2, 0)

This is what I got, but you might want to double check me because I'm not that good at math (this is what I got for the discontinuity);1. f(x)= x^2+6+8/x+4*x+4=0                                      -4 -4                                        x= -4This means that x cannot equal -42. f(x)= (x+2)(x-4)/(x+2)(x+2) *Note: When I did my calculations, I cancelled out all (x+2) binomials except for one in the denominator*f(x)= x-4/x+2 *x+2=0                                          -2 -2                                            x= -2This means x cannot equal -2*You may want to check my work, but I believe that your answer is going to be either C or D. Personally, I assume it's C, but that's just me. Anyway, it's probably going to be C or D, or at least that's what I think.*